(x^2+x-20)/(x^2-25)=0

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Solution for (x^2+x-20)/(x^2-25)=0 equation: 


D( x )

x^2-25 = 0

x^2-25 = 0

x^2-25 = 0

1*x^2 = 25 // : 1

x^2 = 25

x^2 = 25 // ^ 1/2

abs(x) = 5

x = 5 or x = -5

x in (-oo:-5) U (-5:5) U (5:+oo)

(x^2+x-20)/(x^2-25) = 0

x^2+x-20 = 0

x^2+x-20 = 0

DELTA = 1^2-(-20*1*4)

DELTA = 81

DELTA > 0

x = (81^(1/2)-1)/(1*2) or x = (-81^(1/2)-1)/(1*2)

x = 4 or x = -5

(x+5)*(x-4) = 0

((x+5)*(x-4))/(x^2-25) = 0

( x+5 )

x+5 = 0 // - 5

x = -5

( x-4 )

x-4 = 0 // + 4

x = 4

x in { -5} 

x = 4

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